Integrand size = 15, antiderivative size = 91 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=-\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {5 a \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{b^{7/2}} \]
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Time = 0.03 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {49, 52, 65, 223, 212} \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=-\frac {5 a \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{b^{7/2}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}-\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}} \]
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Rule 49
Rule 52
Rule 65
Rule 212
Rule 223
Rubi steps \begin{align*} \text {integral}& = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}+\frac {5 \int \frac {x^{3/2}}{(a+b x)^{3/2}} \, dx}{3 b} \\ & = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \int \frac {\sqrt {x}}{\sqrt {a+b x}} \, dx}{b^2} \\ & = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {(5 a) \int \frac {1}{\sqrt {x} \sqrt {a+b x}} \, dx}{2 b^3} \\ & = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {(5 a) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,\sqrt {x}\right )}{b^3} \\ & = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {(5 a) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {a+b x}}\right )}{b^3} \\ & = -\frac {2 x^{5/2}}{3 b (a+b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {a+b x}}+\frac {5 \sqrt {x} \sqrt {a+b x}}{b^3}-\frac {5 a \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )}{b^{7/2}} \\ \end{align*}
Time = 0.26 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.88 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=\frac {\sqrt {x} \left (15 a^2+20 a b x+3 b^2 x^2\right )}{3 b^3 (a+b x)^{3/2}}+\frac {10 a \text {arctanh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}-\sqrt {a+b x}}\right )}{b^{7/2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(146\) vs. \(2(67)=134\).
Time = 0.11 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.62
method | result | size |
risch | \(\frac {\sqrt {x}\, \sqrt {b x +a}}{b^{3}}+\frac {\left (-\frac {5 a \ln \left (\frac {\frac {a}{2}+b x}{\sqrt {b}}+\sqrt {b \,x^{2}+a x}\right )}{2 b^{\frac {7}{2}}}-\frac {2 a^{2} \sqrt {b \left (x +\frac {a}{b}\right )^{2}-\left (x +\frac {a}{b}\right ) a}}{3 b^{5} \left (x +\frac {a}{b}\right )^{2}}+\frac {14 a \sqrt {b \left (x +\frac {a}{b}\right )^{2}-\left (x +\frac {a}{b}\right ) a}}{3 b^{4} \left (x +\frac {a}{b}\right )}\right ) \sqrt {x \left (b x +a \right )}}{\sqrt {x}\, \sqrt {b x +a}}\) | \(147\) |
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Time = 0.24 (sec) , antiderivative size = 214, normalized size of antiderivative = 2.35 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=\left [\frac {15 \, {\left (a b^{2} x^{2} + 2 \, a^{2} b x + a^{3}\right )} \sqrt {b} \log \left (2 \, b x - 2 \, \sqrt {b x + a} \sqrt {b} \sqrt {x} + a\right ) + 2 \, {\left (3 \, b^{3} x^{2} + 20 \, a b^{2} x + 15 \, a^{2} b\right )} \sqrt {b x + a} \sqrt {x}}{6 \, {\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}, \frac {15 \, {\left (a b^{2} x^{2} + 2 \, a^{2} b x + a^{3}\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-b}}{b \sqrt {x}}\right ) + {\left (3 \, b^{3} x^{2} + 20 \, a b^{2} x + 15 \, a^{2} b\right )} \sqrt {b x + a} \sqrt {x}}{3 \, {\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}}\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 396 vs. \(2 (85) = 170\).
Time = 5.30 (sec) , antiderivative size = 396, normalized size of antiderivative = 4.35 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=- \frac {15 a^{\frac {81}{2}} b^{22} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} \operatorname {asinh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} + 3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}}} - \frac {15 a^{\frac {79}{2}} b^{23} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}} \operatorname {asinh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} + 3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}}} + \frac {15 a^{40} b^{\frac {45}{2}} x^{26}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} + 3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}}} + \frac {20 a^{39} b^{\frac {47}{2}} x^{27}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} + 3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}}} + \frac {3 a^{38} b^{\frac {49}{2}} x^{28}}{3 a^{\frac {79}{2}} b^{\frac {51}{2}} x^{\frac {51}{2}} \sqrt {1 + \frac {b x}{a}} + 3 a^{\frac {77}{2}} b^{\frac {53}{2}} x^{\frac {53}{2}} \sqrt {1 + \frac {b x}{a}}} \]
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Time = 0.28 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.20 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=\frac {2 \, a b^{2} + \frac {10 \, {\left (b x + a\right )} a b}{x} - \frac {15 \, {\left (b x + a\right )}^{2} a}{x^{2}}}{3 \, {\left (\frac {{\left (b x + a\right )}^{\frac {3}{2}} b^{4}}{x^{\frac {3}{2}}} - \frac {{\left (b x + a\right )}^{\frac {5}{2}} b^{3}}{x^{\frac {5}{2}}}\right )}} + \frac {5 \, a \log \left (-\frac {\sqrt {b} - \frac {\sqrt {b x + a}}{\sqrt {x}}}{\sqrt {b} + \frac {\sqrt {b x + a}}{\sqrt {x}}}\right )}{2 \, b^{\frac {7}{2}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 192 vs. \(2 (67) = 134\).
Time = 16.60 (sec) , antiderivative size = 192, normalized size of antiderivative = 2.11 \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=\frac {{\left (\frac {15 \, a \log \left ({\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2}\right )}{b^{\frac {5}{2}}} + \frac {6 \, \sqrt {{\left (b x + a\right )} b - a b} \sqrt {b x + a}}{b^{3}} + \frac {8 \, {\left (9 \, a^{2} {\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{4} + 12 \, a^{3} {\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2} b + 7 \, a^{4} b^{2}\right )}}{{\left ({\left (\sqrt {b x + a} \sqrt {b} - \sqrt {{\left (b x + a\right )} b - a b}\right )}^{2} + a b\right )}^{3} b^{\frac {3}{2}}}\right )} {\left | b \right |}}{6 \, b^{2}} \]
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Timed out. \[ \int \frac {x^{5/2}}{(a+b x)^{5/2}} \, dx=\int \frac {x^{5/2}}{{\left (a+b\,x\right )}^{5/2}} \,d x \]
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